Asked by Monica
A beaker contains 50.0 mL pf 0.953 M solution of a diprotic acid. How many grams of Mg(OH)2 are required to neutralize this solution?
Answers
Answered by
DrBob222
Mg(OH)2 + H2P ==> MgP + 2H2O
moles H2P = M x L = ??
Since 1 mole Mg(OH)2 = 1 mole H2P, then
mols Mg(OH)2 = mols H2P.
grams Mg(OH)2 = moles x molar mass.
moles H2P = M x L = ??
Since 1 mole Mg(OH)2 = 1 mole H2P, then
mols Mg(OH)2 = mols H2P.
grams Mg(OH)2 = moles x molar mass.
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