A beaker contains 50.0 mL of water at 90.0°C. How many calories must be added to raise the temperature of the water to its boiling point (100°C)?

Question

A) 50.0 cal
B) 1.00*10^3
C) 100.0 cal
D) 5.00*10^2
I think the answer is B, but i also think im wrong...

Answer 1

Now we have a heat capacity question

mass of 50 mL = 50 grams

change in temp = 10 degrees C

specific heat capacity of water = 1 cal/gram deg C
so
heat in = 1 cal/g C * 50 g * 10 C
= 500 Calories
= 5 * 10^2 Calories

Answer 2

oh... thnx again Damon! I'll write this 1 down just in case i need it again.