Asked by Saisir le Jour
A beaker contains 50.0 mL of water at 90.0°C. How many calories must be added to raise the temperature of the water to its boiling point (100°C)?
A) 50.0 cal
B) 1.00*10^3
C) 100.0 cal
D) 5.00*10^2
I think the answer is B, but i also think im wrong...
A) 50.0 cal
B) 1.00*10^3
C) 100.0 cal
D) 5.00*10^2
I think the answer is B, but i also think im wrong...
Answers
Answered by
Damon
Now we have a heat capacity question
mass of 50 mL = 50 grams
change in temp = 10 degrees C
specific heat capacity of water = 1 cal/gram deg C
so
heat in = 1 cal/g C * 50 g * 10 C
= 500 Calories
= 5 * 10^2 Calories
mass of 50 mL = 50 grams
change in temp = 10 degrees C
specific heat capacity of water = 1 cal/gram deg C
so
heat in = 1 cal/g C * 50 g * 10 C
= 500 Calories
= 5 * 10^2 Calories
Answered by
Saisir le Jour
oh... thnx again Damon! I'll write this 1 down just in case i need it again.
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