Ask a New Question
Search
Asked by
Anonymous
A beaker contains 199 mL of NaOH with a concentration of .100 mol/L. Calculate the number of moles of NaOH
Answers
Human Answers
1
AI Answers
0
Answered by
DrBob222
moles = M x L = 0.100 x 0.199 =
There are no AI answers yet. The ability to request AI answers is coming soon!
Related Questions
Related
Beaker A and Beaker B both contain water at 20°C . A teaspoon of fine sugar is placed in Beaker A....
Beaker A and Beaker B both contain water at 20°C . A teaspoon of sugar is placed in each beaker. Be...
Beaker and beaker be both contain water at 20 Celsius a teaspoon of fine sugar is placed in beaker a...
Beaker 1 Beaker 2 Beaker 3 Skip to navigation
There is a beaker with 0.4% sucrose solution and the solute potential is -4. Inside the beaker, ther...
A beaker contains 50.0 mL pf 0.953 M solution of a diprotic acid. How many grams of Mg(OH)2 are requ...
A beaker contains 250.0 mL of a 1.00 M HCl solution. How many moles of the acid would remain in the...
if the beaker was wet at the beginning of the experiment for the inital mass of the beaker, how woul...
A 1.00-kg beaker containing 2.0 kg of oil (density = 916 kg/m3) rests on a scale. A 2.00-kg block of...
A beaker contains 100 mL of water. We add 112 mg of KOH(s). What is the concentration of H+ ions?