Asked by anonymous
A stone is thrown with an initial speed of 15 m/s at an angle of 37 above the horizontal from the top of a 35 m building. If g = 9.8 m/s2 and air resistance is negligible, then what is the magnitude of the vertical velocity component of the rock as it hits the ground?
Answers
Answered by
drwls
First calulate the time T when it hits the ground.
y = 35 + Vo sin37*T - (g/2)T^2 = 0
Solve that for time T. You know what Vo and g are. You must solve a quadratic. Take the positive root.
Get the vertical velocity component by solving
Vy (at t = T) = Vo sin 37 - g*T
It should end up being a negative number.
y = 35 + Vo sin37*T - (g/2)T^2 = 0
Solve that for time T. You know what Vo and g are. You must solve a quadratic. Take the positive root.
Get the vertical velocity component by solving
Vy (at t = T) = Vo sin 37 - g*T
It should end up being a negative number.
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