Asked by Mable
a stone that is thrown near the surface of the earth. There is no air resistance. Position increases in the up direction. The initial velocity is 30 m/s at 30 degrees above the horizontal.
what is the velocity when the stone reaches its maximum height ?
what is the acceleration when it reaches its maximum height
what is the time required for the stone to reach the maximum height ?
what is the velocity when the stone reaches its maximum height ?
what is the acceleration when it reaches its maximum height
what is the time required for the stone to reach the maximum height ?
Answers
Answered by
Damon
Vi = 30 sin 30 = 15 = initial speed UP
u = 30 cos 30 = 26 = horizontal speed until caught
v = Vi - 9.81 t
at top v = 0 (First answer)
so at top
t = 15/9.81 = 1.53 seconds upward bound
THE ACCELERATION IS -9.81 m/s^2 the ENTIRE TIME that it is airborne
u = 30 cos 30 = 26 = horizontal speed until caught
v = Vi - 9.81 t
at top v = 0 (First answer)
so at top
t = 15/9.81 = 1.53 seconds upward bound
THE ACCELERATION IS -9.81 m/s^2 the ENTIRE TIME that it is airborne
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