Question
a child standing at the edge of a cliff 100m high throws a stone vertically downwards. The stone hits the sea 4s later. Ignoring air resistance, find the initial speed with which the stone is thrown
Answers
h = -4.9t^2 + vt + 100, where v is the initial velocity
when t = 4, h = 0
0 = -4.9(4) + 4v + 100
4v = -80.4
v = -20.1
the stone was tossed with a velocity of 20.1 m downwards
when t = 4, h = 0
0 = -4.9(4) + 4v + 100
4v = -80.4
v = -20.1
the stone was tossed with a velocity of 20.1 m downwards
Related Questions
you are standing on a 100m tall buiding above a street and your friend is standing vertically below...
A person is standing on the edge of a cliff of height h= 24 m. She throws a stone of mass m=0.2 kg...
A stone thrown vertically upwards with a speed of 12m/s from the edge of Cliff 70m high. Calculate t...
A stone is dropped from the top of a cliff which is 100m high. At the same time another stone is ver...