Asked by Simeon
II.You are standing on the edge of a 50m high cliff and throw a ball vertically up with initial speed of 20m/s: 1.After how long will the ball hit the ground below?
2.Draw the v vs.t graph
2.Draw the v vs.t graph
Answers
Answered by
drwls
Plot the height vs time function
Y (measured from ground below) = 50 + 20 t - 4.9 t^2.
(The 4.9 represents 1/2 the acceleration of gravity, in m/s^2)
Solve for the time when Y = 0. It should be between 5 and 6 seconds.
We do not provide graph-drawing services.
Y (measured from ground below) = 50 + 20 t - 4.9 t^2.
(The 4.9 represents 1/2 the acceleration of gravity, in m/s^2)
Solve for the time when Y = 0. It should be between 5 and 6 seconds.
We do not provide graph-drawing services.
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