Question

II.You are standing on the edge of a 50m high cliff and throw a ball vertically up with initial speed of 20m/s: 1.After how long will the ball hit the ground below?
2.Draw the v vs.t graph

Answer 1

Plot the height vs time function
Y (measured from ground below) = 50 + 20 t - 4.9 t^2.

(The 4.9 represents 1/2 the acceleration of gravity, in m/s^2)

Solve for the time when Y = 0. It should be between 5 and 6 seconds.

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