Question
A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.
Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?
(1 point)
Responses
120p−22<50
120p−22<50
120p−22≤50
120 p minus 22 is less than or equal to 50
120p−22>50
120 p minus 22 is greater than 50
120p−22≥50
120 p minus 22 is greater than or equal to 50
Question 2
(1 point)
The class should sell each cookie for
$0.60.
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Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?
(1 point)
Responses
120p−22<50
120p−22<50
120p−22≤50
120 p minus 22 is less than or equal to 50
120p−22>50
120 p minus 22 is greater than 50
120p−22≥50
120 p minus 22 is greater than or equal to 50
Question 2
(1 point)
The class should sell each cookie for
$0.60.
Skip to navigation
Answers
GPT-4o mini
To determine the possible prices (p) that the class can sell the cookies for to reach its goal of making at least $50 after covering the costs, we can set up the following inequality:
1. The total revenue from selling the cookies is given by \( 120p \) (where \( p \) is the price per cookie).
2. The total cost to make the cookies is $22.
3. The class wants to make at least $50 after covering the cost, so we need to express this condition mathematically.
To make at least $50 after the costs, we set up the inequality:
\[ 120p - 22 \geq 50 \]
This means:
- Total revenue (120p) minus total costs ($22) should be greater than or equal to $50.
Thus, the correct option is:
**120p - 22 ≥ 50**
For Question 2, to find the price per cookie when they want to make at least $50, we can solve the inequality:
1. Start with \( 120p - 22 ≥ 50 \).
2. Add 22 to both sides: \( 120p ≥ 72 \).
3. Divide by 120: \( p ≥ 0.60 \).
Therefore, the class should sell each cookie for **at least $0.60** to reach their goal.
1. The total revenue from selling the cookies is given by \( 120p \) (where \( p \) is the price per cookie).
2. The total cost to make the cookies is $22.
3. The class wants to make at least $50 after covering the cost, so we need to express this condition mathematically.
To make at least $50 after the costs, we set up the inequality:
\[ 120p - 22 \geq 50 \]
This means:
- Total revenue (120p) minus total costs ($22) should be greater than or equal to $50.
Thus, the correct option is:
**120p - 22 ≥ 50**
For Question 2, to find the price per cookie when they want to make at least $50, we can solve the inequality:
1. Start with \( 120p - 22 ≥ 50 \).
2. Add 22 to both sides: \( 120p ≥ 72 \).
3. Divide by 120: \( p ≥ 0.60 \).
Therefore, the class should sell each cookie for **at least $0.60** to reach their goal.