Question

A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.

Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?

(1 point)
Responses

120p−22<50
120p−22<50

120p−22≤50
120 p minus 22 is less than or equal to 50

120p−22>50
120 p minus 22 is greater than 50

120p−22≥50
120 p minus 22 is greater than or equal to 50
Question 2
(1 point)
The class should sell each cookie for
$0.60.
Skip to navigation

Answer 1

To determine the possible prices (p) that the class can sell the cookies for to reach its goal of making at least $50 after covering the costs, we can set up the following inequality:

1. The total revenue from selling the cookies is given by \( 120p \) (where \( p \) is the price per cookie).
2. The total cost to make the cookies is $22.
3. The class wants to make at least $50 after covering the cost, so we need to express this condition mathematically.

To make at least $50 after the costs, we set up the inequality:

\[ 120p - 22 \geq 50 \]

This means:

- Total revenue (120p) minus total costs ($22) should be greater than or equal to $50.

Thus, the correct option is:

**120p - 22 ≥ 50**

For Question 2, to find the price per cookie when they want to make at least $50, we can solve the inequality:

1. Start with \( 120p - 22 ≥ 50 \).
2. Add 22 to both sides: \( 120p ≥ 72 \).
3. Divide by 120: \( p ≥ 0.60 \).

Therefore, the class should sell each cookie for **at least $0.60** to reach their goal.