Asked by Sarah
Prove tanAsin2A=2sin^2a
Answers
Answered by
Reiny
LS
= (tanA)(sin2A)
= sinA/cosA(2sinAcosA)
= 2sin^2 A
= RS
= (tanA)(sin2A)
= sinA/cosA(2sinAcosA)
= 2sin^2 A
= RS
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