Asked by Veronica

prove:
2sinx+sin2x = 2sin^3(x)/1-cosx
Answered by Reiny
LS = 2sinx + 2sinxcosx
= 2sinx(1 + cosx)
= 2sinx(1 + cosx)<b>(1-cosx)/(1-cosx)</b>
= 2sinx(1 - cos^2x)/(1-cosx)
= 2sinx(sin^2x)/(1-cosx)
= 2sin^3x/(1-cosx)
= RS
Answered by Veronica
Thank you Reiny!
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