Asked by Anonymous
prove that
1+sin2x-cos2x / sin2x+cos2x = tanx
1+sin2x-cos2x / sin2x+cos2x = tanx
Answers
Answered by
Reiny
not true, so it can't be proven the way you typed it
probably <b>needs brackets</b>
counterexample:
let x = 30°
LS = 1 + sin60° - cos60°/sin60° + cos60°
= 1 + √3/2 - (1/2) / (√3/2) + 1/2
= 3/2 + √3/2 - 1/√3
RS = tan 30 = 1/√3 ≠ LS
probably <b>needs brackets</b>
counterexample:
let x = 30°
LS = 1 + sin60° - cos60°/sin60° + cos60°
= 1 + √3/2 - (1/2) / (√3/2) + 1/2
= 3/2 + √3/2 - 1/√3
RS = tan 30 = 1/√3 ≠ LS
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