Asked by SIMPLIFY:
Sin2x/1-Cos2x
Answers
Answered by
Reiny
You need two identities:
sin2A = sinAcosA and
cos2A = 1 - 2sin^2A
so Sin2x/(1-Cos2x)
= 2sinxcosx/(1 - (1-2sin^2x))
= 2sinxcosx/(2sin^2x)
= cosx/sinx
= cotx
sin2A = sinAcosA and
cos2A = 1 - 2sin^2A
so Sin2x/(1-Cos2x)
= 2sinxcosx/(1 - (1-2sin^2x))
= 2sinxcosx/(2sin^2x)
= cosx/sinx
= cotx
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