Asked by Venkatesh
2sin^2 A + 5cosA = 4 , Prove that cos A = 1/2
Answers
Answered by
Reiny
2sin^2 A + 5cosA = 4
2(1 - cos^2 A) + 5cosA - 4 = 0
2cos^2 A - 5cosA + 2 = 0
(2cosA -1)(cosA - 2) = 0
cosA = 1/2 or cosA = -2, the latter is not possible,
so cosA = 1/2
2(1 - cos^2 A) + 5cosA - 4 = 0
2cos^2 A - 5cosA + 2 = 0
(2cosA -1)(cosA - 2) = 0
cosA = 1/2 or cosA = -2, the latter is not possible,
so cosA = 1/2
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