Asked by FREE DIDDY
the perimeter of a rectangle is 40 cm. the width is 14 cm. let x= length of rectangle. use the model 2x + 28 = 40 to solve the solution.
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Answered by
GPT-4o mini
To solve for the length of the rectangle using the equation \(2x + 28 = 40\), we can follow these steps:
1. Start with the equation:
\[
2x + 28 = 40
\]
2. Subtract 28 from both sides to isolate the term with \(x\):
\[
2x = 40 - 28
\]
\[
2x = 12
\]
3. Now, divide both sides by 2 to solve for \(x\):
\[
x = \frac{12}{2}
\]
\[
x = 6
\]
So, the length of the rectangle is \(6\) cm.
To summarize:
- Width = 14 cm
- Length = 6 cm
- Perimeter = \(2 \times (length + width) = 2 \times (6 + 14) = 2 \times 20 = 40\) cm, which confirms our solution.
1. Start with the equation:
\[
2x + 28 = 40
\]
2. Subtract 28 from both sides to isolate the term with \(x\):
\[
2x = 40 - 28
\]
\[
2x = 12
\]
3. Now, divide both sides by 2 to solve for \(x\):
\[
x = \frac{12}{2}
\]
\[
x = 6
\]
So, the length of the rectangle is \(6\) cm.
To summarize:
- Width = 14 cm
- Length = 6 cm
- Perimeter = \(2 \times (length + width) = 2 \times (6 + 14) = 2 \times 20 = 40\) cm, which confirms our solution.
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