The perimeter of a rectangle is 122m. The length of the rectangle is 11m less than 5 times the width. Find the dimensions of the rectangle.

Answer 1

P = Perimeter

L = Length

W = Width

P = 2 L + 2 W

P = 2 ( L + W )

P = 122 m

L = 5 W - 11

122 = 2 ( 5 W - 11 + W )

122 = 2 ( 6 W - 11 )

122 = 12 W - 22

122 + 22 = 12 W

12 W = 144 Diwidw both sides with 12

W = 144 / 12

W = 12 m

L = 5 W - 11

L = 5 * 12 - 11

L = 60 - 11

L = 49 m

P = 2 ( L + W )

P = 2 ( 49 + 12 )

P = 2 * 61

P = 122 m