Asked by Bababa

Calculate the solubility (in g/L) of silver carbonate in water at 25°C if the Ksp for Ag2CO3 is 8.4 x 10^-12
Answered by DrBob222
Ag2CO3(s) ==> 2Ag^+ + CO3^-2

Ksp = (Ag^+)^2(CO3^-2)
Set up an ICE chart and solve which gives the solubility in moles/L, then convert that to grams. Post your work if you get stuck.
Answered by Samuel
3.34716475*10^-04
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