Calculate the solubility of oxygen in water at a partical pressure of 02 of 460 torrat 25 degree celsius

Do you have a graph that gives solubility at any other condition or do you have the Henry's law constant?

henrys lawconstant for oxygen in water is 1.28 X 10^-3 mol/(atm.L)

You know Henry's Law is written a bunch of ways. Since you gave k in mol/atm-L I think that means you are using

c = pk
c in mols/L = (640/760)*1.23E-3 = ?

To calculate the solubility of oxygen in water at a given partial pressure and temperature, you can use Henry's Law. Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.

The equation for Henry's Law is:

C = k * P

Where:
C is the concentration or solubility of the gas in the liquid,
k is the Henry's Law constant for the gas and solvent, and
P is the partial pressure of the gas above the liquid.

To calculate the solubility of oxygen in water, you need to know the Henry's Law constant for oxygen and water. The Henry's Law constant for oxygen in water at 25 °C is approximately 0.0359 mol/L·atm.

In this case, the partial pressure of oxygen (O2) is given as 460 torr.

Let's calculate the solubility of oxygen in water:

C = k * P

C = 0.0359 mol/L·atm * (460 torr / 760 torr/atm)

C = 0.02176 mol/L

Therefore, the solubility of oxygen in water at a partial pressure of O2 of 460 torr at 25 °C is approximately 0.02176 mol/L.