Asked by Anonymous
Calculate the solubility (in M units) of ammonia gas in water at 298 K
and a partial pressure of 5.00 bar. The Henry’s law constant for ammonia gas at 298 K is 58.0 M/atm and 1 bar=0.9869 atm
Epress your answer in molarity to three significant figures.
and a partial pressure of 5.00 bar. The Henry’s law constant for ammonia gas at 298 K is 58.0 M/atm and 1 bar=0.9869 atm
Epress your answer in molarity to three significant figures.
Answers
Answered by
DrBob222
k = C/p = 58.0. Convert 5 bar pressure to atm. 5 bar x (0.9869 atm/1 bar) = 4.93 atm
58.0 = C/4.93 atm
Solve for C in mols/L = M
Post your work if you get stuck.
58.0 = C/4.93 atm
Solve for C in mols/L = M
Post your work if you get stuck.
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