Asked by Anonymous

Calculate the solubility (in grams per 1.00 102 mL of solution) of magnesium hydroxide in a solution buffered at pH = 9

the ksp of Mg(oh)2 = 2.06e-13

Answers

Answered by DrBob222
........Mg(OH)2 ==> Mg^2+ + 2OH^-
E........x...........x.......2x

Ksp = 2.06E-13 = (Mg^2+)(OH^-)
For (Mg^+) substitute x
For (OH^-)^2 substitute (2x + 1E-5)^2 [note: 2x for the Mg(OH)2 and 1E-5 for the OH^- concn of a soln with pH = 9
Solve for x = solubility in mols/L, then correct that to mols/100 mL, then to g/100 mL.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions