Question
Select the equivalent expression.
\[\left(6^{-4}\cdot 8^{-7}\right)^{-9}=?\]
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[\dfrac{1}{6^{13}\cdot 8^{16}}\]
A
\[\dfrac{1}{6^{13}\cdot 8^{16}}\]
(Choice B)
\[6^{5}\cdot 8^{2}\]
B
\[6^{5}\cdot 8^{2}\]
(Choice C)
\[6^{36}\cdot 8^{63}\]
C
\[6^{36}\cdot 8^{63}\]
\[\left(6^{-4}\cdot 8^{-7}\right)^{-9}=?\]
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[\dfrac{1}{6^{13}\cdot 8^{16}}\]
A
\[\dfrac{1}{6^{13}\cdot 8^{16}}\]
(Choice B)
\[6^{5}\cdot 8^{2}\]
B
\[6^{5}\cdot 8^{2}\]
(Choice C)
\[6^{36}\cdot 8^{63}\]
C
\[6^{36}\cdot 8^{63}\]
Answers
GPT-4o mini
To solve the expression \(\left(6^{-4}\cdot 8^{-7}\right)^{-9}\), we can use the properties of exponents.
1. Apply the exponent rule \((a \cdot b)^m = a^m \cdot b^m\):
\[
\left(6^{-4} \cdot 8^{-7}\right)^{-9} = \left(6^{-4}\right)^{-9} \cdot \left(8^{-7}\right)^{-9}
\]
2. Apply the exponent rule \(a^{-m} = \frac{1}{a^m}\) and also \(a^{m \cdot n} = a^{m \cdot n}\):
\[
\left(6^{-4}\right)^{-9} = 6^{36} \quad \text{and} \quad \left(8^{-7}\right)^{-9} = 8^{63}
\]
3. Therefore, we can combine these:
\[
6^{36} \cdot 8^{63}
\]
So, the final equivalent expression is:
\[
6^{36} \cdot 8^{63}
\]
Thus, the answer is **Choice C**: \[6^{36} \cdot 8^{63}\].
1. Apply the exponent rule \((a \cdot b)^m = a^m \cdot b^m\):
\[
\left(6^{-4} \cdot 8^{-7}\right)^{-9} = \left(6^{-4}\right)^{-9} \cdot \left(8^{-7}\right)^{-9}
\]
2. Apply the exponent rule \(a^{-m} = \frac{1}{a^m}\) and also \(a^{m \cdot n} = a^{m \cdot n}\):
\[
\left(6^{-4}\right)^{-9} = 6^{36} \quad \text{and} \quad \left(8^{-7}\right)^{-9} = 8^{63}
\]
3. Therefore, we can combine these:
\[
6^{36} \cdot 8^{63}
\]
So, the final equivalent expression is:
\[
6^{36} \cdot 8^{63}
\]
Thus, the answer is **Choice C**: \[6^{36} \cdot 8^{63}\].