Show which of the following points is part of the solution set for the inequality y≤25x+1

.(1 point)
Responses

(10,4)
left parenthesis 10 comma 4 right parenthesis

(10,5.5)
left parenthesis 10 comma 5.5 right parenthesis

(10,6)
left parenthesis 10 comma 6 right parenthesis

(−10,6)

1 answer

To determine if a point is part of the solution set for the inequality \( y \leq 25x + 1 \), we can substitute the coordinates of each point into the inequality and see if it holds true.

  1. For the point \( (10, 4) \): \[ y = 4 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 250 + 1 = 251 \] \[ 4 \leq 251 \quad \text{(True)} \]

  2. For the point \( (10, 5.5) \): \[ y = 5.5 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 251 \] \[ 5.5 \leq 251 \quad \text{(True)} \]

  3. For the point \( (10, 6) \): \[ y = 6 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 251 \] \[ 6 \leq 251 \quad \text{(True)} \]

  4. For the point \( (-10, 6) \): \[ y = 6 \quad \text{and} \quad 25x + 1 = 25(-10) + 1 = -250 + 1 = -249 \] \[ 6 \leq -249 \quad \text{(False)} \]

Based on the evaluations:

  • \( (10, 4) \): True
  • \( (10, 5.5) \): True
  • \( (10, 6) \): True
  • \( (-10, 6) \): False

Every point except \( (-10, 6) \) satisfies the inequality \( y \leq 25x + 1 \). Thus, the points \( (10, 4) \), \( (10, 5.5) \), and \( (10, 6) \) are part of the solution set.