To determine which labeled point is a viable solution for Lina’s earnings represented by the inequality \( 25x + 15y \geq 200 \), we will substitute each of the given points into the inequality and check if they satisfy it.
1. **Point (2, 3):**
- Substitute \( x = 2 \) and \( y = 3 \):
\[
25(2) + 15(3) = 50 + 45 = 95
\]
- Check: \( 95 \geq 200 \) (False)
2. **Point (20, 11.5):**
- Substitute \( x = 20 \) and \( y = 11.5 \):
\[
25(20) + 15(11.5) = 500 + 172.5 = 672.5
\]
- Check: \( 672.5 \geq 200 \) (True)
3. **Point (10, 10):**
- Substitute \( x = 10 \) and \( y = 10 \):
\[
25(10) + 15(10) = 250 + 150 = 400
\]
- Check: \( 400 \geq 200 \) (True)
After evaluating all points:
- (2, 3) is not a viable solution.
- (20, 11.5) is a viable solution.
- (10, 10) is a viable solution.
**Conclusion:** The labeled point (20, 11.5) is a viable solution for the inequality \( 25x + 15y \geq 200 \).