Asked by Sarah Fuller
prove:
cos*2x=csc*2x-2/csc*2x
cos*2x=csc*2x-2/csc*2x
Answers
Answered by
bobpursley
I think you must be usint * as the power to, as in ^
right side: (csc^2 x - 2)/csc^2 x
(1-2sin^2x) = 1-2(1-cos^2x)=-1+2cos^2x
which is clearly not an identity.
So I am not certain what your problem is.
right side: (csc^2 x - 2)/csc^2 x
(1-2sin^2x) = 1-2(1-cos^2x)=-1+2cos^2x
which is clearly not an identity.
So I am not certain what your problem is.
Answered by
Reiny
Your use of * in the last 3 posts will cause confusion
traditionally
* means multiplication
/ means division and
^ means "to the exponent"
so you want to say
cos^2 x=csc^2 x-2/csc^2 x
but that statement is not true for all x's, I just tried any x and it did not work.
Use brackets to establish the proper order of operations.
traditionally
* means multiplication
/ means division and
^ means "to the exponent"
so you want to say
cos^2 x=csc^2 x-2/csc^2 x
but that statement is not true for all x's, I just tried any x and it did not work.
Use brackets to establish the proper order of operations.
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