Asked by Kate
How to prove this
(e^(2^-1 i3pi) - e^-(2^-1 i3pi))/(2i) = -1
if you could show me this that would be really great
btw e is eulers number
i = imaginary number sqrt -1
and pi = 3.14...
THANKS!!!
(e^(2^-1 i3pi) - e^-(2^-1 i3pi))/(2i) = -1
if you could show me this that would be really great
btw e is eulers number
i = imaginary number sqrt -1
and pi = 3.14...
THANKS!!!
Answers
Answered by
drwls
One definition of sin x is
sinx = (e^ix - e^-ix)/2i
That means that your expression is
sin (3 pi/2)
The sine of that angle is -1
sinx = (e^ix - e^-ix)/2i
That means that your expression is
sin (3 pi/2)
The sine of that angle is -1
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