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Asked by Kewal

If A + B + C = 180° prove that
Sin2A + sin2B – sin2C = 4cosAcosBsinC

13 years ago

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Answered by Tanzeel
4cosAcosBsinC
8 years ago
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If A + B + C = 180° prove that
Sin2A + sin2B – sin2C = 4cosAcosBsinC

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