Asked by Mutane
                Prove that x=2 in 3^x + 4^x = 5^x? 
            
            
        Answers
                    Answered by
            Reiny
            
    Just substitute 
LS = 3^x + 4^x
= 3^2 + 4^2 = 25
RS = 5^x = 5^2 = 25
so LS = RS
You probably should have recognized the simplest
Pythagorean triangle relationship,
3^2 + 4^2 = 5^2, so you have the right-angled triangle with sides
3, 4, and 5
    
LS = 3^x + 4^x
= 3^2 + 4^2 = 25
RS = 5^x = 5^2 = 25
so LS = RS
You probably should have recognized the simplest
Pythagorean triangle relationship,
3^2 + 4^2 = 5^2, so you have the right-angled triangle with sides
3, 4, and 5
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