Asked by Mutane
Prove that x=2 in 3^x + 4^x = 5^x?
Answers
Answered by
Reiny
Just substitute
LS = 3^x + 4^x
= 3^2 + 4^2 = 25
RS = 5^x = 5^2 = 25
so LS = RS
You probably should have recognized the simplest
Pythagorean triangle relationship,
3^2 + 4^2 = 5^2, so you have the right-angled triangle with sides
3, 4, and 5
LS = 3^x + 4^x
= 3^2 + 4^2 = 25
RS = 5^x = 5^2 = 25
so LS = RS
You probably should have recognized the simplest
Pythagorean triangle relationship,
3^2 + 4^2 = 5^2, so you have the right-angled triangle with sides
3, 4, and 5