Asked by Tyler

A concert loudspeaker suspended high off the ground emits 35 W of sound power. A small
microphone with a 1.0 cm2 area is 50 m from the speaker.
(a) What is the sound intensity at the position of the microphone?
(b) How much sound energy impinges on the microphone each second?

Answers

Answered by bobpursley
a) is a standard formula

b) what is the surface area at 50m

Area= 4PI(50)^2

area of mike= 1cm^2*=(1m/100cm)^2=1E-4m^2

sound energy=35*1E-4/4PI2500

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