Add the polynomial expressions 2r^2−3r+4 and −2r^2+3r+6 (1 point)

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), you combine like terms.

1. Combine the \(r^2\) terms:
\[
2r^2 + (-2r^2) = 0r^2
\]

2. Combine the \(r\) terms:
\[
-3r + 3r = 0r
\]

3. Combine the constant terms:
\[
4 + 6 = 10
\]

Putting it all together, we have:
\[
0r^2 + 0r + 10 = 10
\]

So, the sum of the polynomial expressions is \(10\).