Add the polynomial expressions 2r ^ 2 - 3r + 4 and - 2r ^ 2 + 3r + 6 (1 point)

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), you combine like terms:

1. **Combine the \(r^2\) terms**:
\[
2r^2 + (-2r^2) = 0r^2
\]

2. **Combine the \(r\) terms**:
\[
-3r + 3r = 0r
\]

3. **Combine the constant terms**:
\[
4 + 6 = 10
\]

Now, putting it all together, we have:

\[
0r^2 + 0r + 10 = 10
\]

Thus, the sum of the two polynomial expressions is \(10\).