Add the polynomial expressions 2r^2−3r +4 and −2r^2+3r+6 .(1 point)

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), we combine like terms.

1. **Combine the \(r^2\) terms**:
\[
2r^2 + (-2r^2) = 0r^2
\]

2. **Combine the \(r\) terms**:
\[
-3r + 3r = 0r
\]

3. **Combine the constant terms**:
\[
4 + 6 = 10
\]

Now, putting it all together:
\[
0r^2 + 0r + 10 = 10
\]

Thus, the result of adding the two polynomial expressions is:
\[
\boxed{10}
\]