Asked by dale
A rubber ball is attached to a paddle by a rubber band. The ball is initially moving away from the paddle with a speed of 5.5 m/s. After 0.35 s, the ball is moving toward the paddle with a speed of 5.5 m/s. What is the average acceleration of the ball during that 0.35 s? Give magnitude and direction.
Answers
Answered by
Damon
Call away direction +
acceleration = change in velocity / change in time
= (Vfinal - Vinitial) / (Tfinal - Tinitial)
= (-5.5 - 5.5) / .35
acceleration = change in velocity / change in time
= (Vfinal - Vinitial) / (Tfinal - Tinitial)
= (-5.5 - 5.5) / .35
Answered by
Anonymous
A skateboard rider starts from rest and maintains a constant acceleration of 10.50 m/s2 for 8.4 s. what is the rider's displacement during this time?
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