Asked by Daniel
A rubber ball filled with air has a diameter of 25.0 cm and a mass of 0.540 kg. What force is requiered to hold the ball in equilibrium immediately below the surface of water in a swimming pool?
Start equation out by using sumF = ma
Answer is 74.9 N
I just need to know how to work it and start it out.
Thx
Start equation out by using sumF = ma
Answer is 74.9 N
I just need to know how to work it and start it out.
Thx
Answers
Answered by
bobpursley
force bouyance= weight+ forceholdingit down.
bouyancy is the weight of the water it displaces, or densitywater*g*volume or
= 4/3 PI r^2 * density water*g
where density water is in kg/m^3, r is in meters, SI throughout.
bouyancy is the weight of the water it displaces, or densitywater*g*volume or
= 4/3 PI r^2 * density water*g
where density water is in kg/m^3, r is in meters, SI throughout.
Answered by
Daniel
Ok cool thanks! Is there anyway to start the equation out with sumF = ma though? That is what my teacher stated to do on the paper.
Answered by
drwls
Since the ball is being held, it is not accelerating. Therefore a = 0
That leads to
sumF = 0
Then follow BobPursley's advice
That leads to
sumF = 0
Then follow BobPursley's advice
Answered by
Daniel
Alrighty sounds good. Got it. THx
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