Asked by Pema
In triangle ABC, sinA=0.6, a=10 and b=7. Find sinB
Answers
Answered by
Damon
sin A/a = sin B/b law of sines
so
sinB = (b/a) sinA
= .7 sin A = .7*.6 = .42
so
sinB = (b/a) sinA
= .7 sin A = .7*.6 = .42
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