Asked by hrideshna
tanA+sinA=p, tanA-sinA=q shows that p^2+q^2
Answers
Answered by
Damon
let
c = tan A
d = sin A
P = c + d so p^2 = c^2 + 2 c d + d^2
q = c - d so q^2 = c^2 - 2 c d + d^2
p^2+q^2 = 2 (c^2 + d^2)
= 2 (tan^2 A + sin^2 A)
so what is the question?
c = tan A
d = sin A
P = c + d so p^2 = c^2 + 2 c d + d^2
q = c - d so q^2 = c^2 - 2 c d + d^2
p^2+q^2 = 2 (c^2 + d^2)
= 2 (tan^2 A + sin^2 A)
so what is the question?
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