Asked by Collins
tanA=ntanB
sinA=msinB
find cos^2A in terms of 'm' and 'n'
plz help
sinA=msinB
find cos^2A in terms of 'm' and 'n'
plz help
Answers
Answered by
Steve
taking reciprocals, we have
cot^2A = 1/n^2 cot^2B
csc^2A = 1/m^2 csc^2B
m^2 csc^2A - n^2 cot^2A = csc^2B-cot^2B = 1
Now you should be able to get things down to cos^2A
cot^2A = 1/n^2 cot^2B
csc^2A = 1/m^2 csc^2B
m^2 csc^2A - n^2 cot^2A = csc^2B-cot^2B = 1
Now you should be able to get things down to cos^2A
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