Question
TanA=√2-1 then find secA.sinA+tan^2A-cosecA
Answers
Steve
If you draw the triangle, you can see that
tanA = √2-1
sinA = (√2-1)/(4-2√2)
secA = (4-2√2)
So,
secA.sinA+tan^2A-cosecA
= (4-2√2) * (√2-1)/(4-2√2) + (3-2√2) - (4-2√2)/(√2-1)
= 2-3√2
tanA = √2-1
sinA = (√2-1)/(4-2√2)
secA = (4-2√2)
So,
secA.sinA+tan^2A-cosecA
= (4-2√2) * (√2-1)/(4-2√2) + (3-2√2) - (4-2√2)/(√2-1)
= 2-3√2