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(secA-cosecA)(1+tanA+cotA)= tanAsecA-cotAcosecA
7 years ago

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Arora
(seca-coseca)(1+tana+cota)
= seca - coseca + seca*tana - coseca*tana + seca*cota - coseca*cota

= seca - coseca + seca*tana - seca + coseca - coseca*cota

= secatana - cosecacota
7 years ago

Related Questions

tanA/secA-1 + tanA/secA+1 = 2 cosecA express secA in terms of cotA? can you pleas say how to solve this?? Prove that [1+cotA-CosecA] [1+tanA+secA] = 2 sinA+cosA=p and secA+CosecA=q then show that q[p^2-1]=2p sinA+cosA=p ,secA+cosecA=q (cosA)^2/[2-2(sinA)^2-(cosecA)^2]=p^2/(2(p^2)-q^2 If secB=x,tanB=y(cosecA-cotA)=4/3,sinA+cosA=? (secA + tanA-1)(secA-tanA+1)=2tanA M=sina+cosa N=seca+coseca M^2/2M^2-N^2=cosa^2/2-2sina^2-coseca^2 1÷(tana-seca)-(1÷tana-seca)=-2sec (TanA/1-cotA)+CotA/1-TanA
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