SinA + sinB/sinA - sinB= tanA+B/2cotA-B/2

sina=^10 sinb=^5 find a+b if a,b are acute angles

if sinA+sinB=x and cosA-cosB=y then find tan[(A-B)/2]

If sinA + sinB = a and cosA + cosB = b, find the value of tanA-B/2

If 1/sinA+1/cosA =1/sinB+1/cosB, prove that: cot(A/2+B/2) = TanA. TanB

If sinA+sinB=1/2 and cosA+cosB=1/2 then the value of tanA+tanB

IF (1/SinA)+(1/cosA)= (1/sinB)+(1/cosB) Prove that cot((A+B)/2)=tanA tanB Please helppppppppppp

12. IF 1/SinA+1/CosA=1/SinB+1/CosB ,PROVE THAT: Cot{(A+B)/2}=TanA.TanB

a+b+c=180,show that sina+sinb+sinc=4cosa/2cosb/2cosc/2

A+B=90 then sina sinb=

sinA.sin(B – C) + sinB.sin(C – A) + sinC.sin(A – B) = 0

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