Asked by anya
A+B=90 then sina sinb=
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Answered by
Damon
I assume you mean 90 degrees so right triangle and a^2 + b^2 = c^2
sin A = a/c
sin B = b/c
sin A sin B = a b/ c^2 = a b /(a^2+b^2)
sin A = a/c
sin B = b/c
sin A sin B = a b/ c^2 = a b /(a^2+b^2)
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