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Asked by Sarah

The perimiter of a rectangle is 220 inches. The length exceeds the width by 68 inches. Find the length and the width.
15 years ago

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Answered by drwls
2(L + W) = 220

L = W + 68

Solve thse two equations simultaneously.

Try substituting W + 68 for L in the first equation.
15 years ago
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The perimiter of a rectangle is 220 inches. The length exceeds the width by 68 inches. Find the length and the width.

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