Asked by -Untamed-
Consider the rectangle with an area of 24x^3-54x^2-15x, with a side length of 6x^2-15x. Write and simplify an expression for the length of the rectangle.
^ Could someone please show me how to do this?
^ Could someone please show me how to do this?
Answers
Answered by
Steve
It's just an exercise in polynomial long division. In fact, looking more closely, it's even easier.
area = length * width
length = area/width
Now, 24x^3-54x^2-15x
= x(24x^2-54x-15)
= 3x(8x^2 - 18x - 5)
= 3x(2x-5)(4x+1)
6x^2 - 15x
= 3x(2x-5)
So, length = 3x(2x-5)(4x+1) / 3x(2x-5)
= 4x+1
area = length * width
length = area/width
Now, 24x^3-54x^2-15x
= x(24x^2-54x-15)
= 3x(8x^2 - 18x - 5)
= 3x(2x-5)(4x+1)
6x^2 - 15x
= 3x(2x-5)
So, length = 3x(2x-5)(4x+1) / 3x(2x-5)
= 4x+1
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