Asked by JJ
Water flows in a cylindrical, horizontal pipe. As the pipe widens to twice its initial diameter the pressure in the pipe changes.
Calculate the change in pressure between the wide and narrow regions of the pipe. Give your answer as an expression in terms of the density of water, rho, and initial speed v.
Calculate the change in pressure between the wide and narrow regions of the pipe. Give your answer as an expression in terms of the density of water, rho, and initial speed v.
Answers
Answered by
drwls
The incompressible continuity equation
(Area)*(velocity) = constant
tells you that the speed is 1/4 as high in the wider section. Thus v' = v/4 is the new velocity.
Use the Bernoulli equation to complete the problem. The pressure increase equals the decrease in (1/2)(rho)V^2
Show your work if you need additional assistance.
(Area)*(velocity) = constant
tells you that the speed is 1/4 as high in the wider section. Thus v' = v/4 is the new velocity.
Use the Bernoulli equation to complete the problem. The pressure increase equals the decrease in (1/2)(rho)V^2
Show your work if you need additional assistance.
Answered by
desalegn
acertain solid weights 20N in air and 15N when submarged wholly in oil with arclativ density of 0.8 determine a)the volume of oil displaced b)the density of solid
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