Question
Water flows at 0.25L/s through a 9.0-m-long garden hose 2.0cm in diameter that is lying flat on the ground.The temperature of the water is 20degC. What is the gauge pressure of the water where it enters the hose? in Pa
Answers
Anonymous
Use the formula
Q=pi*R^4*P/8*n*L
n= viscosity of the fluid
L= length
R= radius
Q=pi*R^4*P/8*n*L
n= viscosity of the fluid
L= length
R= radius
KIM
THANKS
After conversions Q = 2.5*10-4; if I plug this into my equation:
p= [(8nL)*Q]/pi*R^4
p=[(8*(1.0*10-3 Pa*s)*9m)*2.5*10-4m3/s]/pi*0.01m4
p= 1.8*10-5/3.14*10-8 p = 573.2 Pa
After conversions Q = 2.5*10-4; if I plug this into my equation:
p= [(8nL)*Q]/pi*R^4
p=[(8*(1.0*10-3 Pa*s)*9m)*2.5*10-4m3/s]/pi*0.01m4
p= 1.8*10-5/3.14*10-8 p = 573.2 Pa