Asked by Chai

Water flows at 2.4 m/s through a garden hose of diameter 1.59 cm and emerges from a nozzle of
radius 0.64 cm. If the nozzle is directed vertically upward, to what height would the water rise?

Answers

Answered by Damon
all you need to know is the speed of a hunk of water headed up.
Q = flow rate = hose area * v
Q = pi (.0159)^2 /4 * 2.4
Q = .000477 m^3/second
but
Q = flow rate = nozzle area * speed
Vi = initial speed up

.000477 m/s = pi r^2 Vi
.000477 = pi (.0064)^2 Vi

Vi = 3.7 m/s
Now we have a plain old throw it straight up problem with initial speed up of 3.7 m/s
v = Vi - 9.81 t
v = 0 at top
t = .373 seconds rising
then
h = 4.9 t^2
h = .68 meters



There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions