Asked by Katy

Water flows into a cylindrical tank through pipe 1 at a rate of 25 ft/s and leaves through pipe 2 at 10 ft/s and through pipe 3 at 12 ft/s. Pipe 4 is an open air vent. Internal diameters of the pipes are: D1=3 in, D2= 2 in, D3=2.5 in, D4=2 in. Calculate a) dh/dt and b) the average velocity of the air escaping through pipe 4 assuming incompressible flow. (Tank's diameter: 2 ft)
Answered by bobpursley
find dV/dt out of the exit pipe. (if you are not in calculus,dV/dt is the flow rate of the water out). That will equal the flow rate of the air coming in, then convert that flow rate to velocity.
Answered by SLU
w w w . u n i m a s r . n e t / u m s / u p l o a d / n e w u p l o a d s / u p l o a d s 2 0 0 9 / u p l o a d s D e c / U n i M a s r . c o m _ a 5 b f e 1 0 3 8 2 0 f 4 a 9 e 3 8 6 9 0 2 f 3 e a 4 e 2 e 5 4 . p d f


Jiskha wouldn't let me post the url so I added spaces but this site has the answer
Answered by Anonymous
The tank shown below is 1/2 of water.then a spherical wrecking ball with radius of 2 ft is dropped in the tank.how far Will the water level rise once the sphere is completely submerged?
There are no AI answers yet. The ability to request AI answers is coming soon!