Asked by samuel
What volume of 0.200 M H2SO4 will be needed to neutralize 50mL of 0.178 N NaOH?
i don't even know how to start
i don't even know how to start
Answers
Answered by
bobpursley
The sulfuric acid is .4N .
.4N(volume)=.178N*50ml
solve for volume
.4N(volume)=.178N*50ml
solve for volume
Answered by
samuel
3.56mL?
Answered by
DrBob222
No, not even close.
You want (50*0.178)/0.4 = ??
You want (50*0.178)/0.4 = ??
Answered by
samuel
22.25 ml?
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