Question
What volume of 1.45 H2SO4 is required to neutralize .050L of .75M KOH?
Answers
DrBob222
2KOH + H2SO4 ==> K2SO4 + 2H2O
mols KOH = M x L = ?
mols H2SO4 = 1/2 that looking at the coefficients in the balanced equation.
Then M H2SO4 = mols H2SO4/L H2SO4. You know mols and M, solve for L.
mols KOH = M x L = ?
mols H2SO4 = 1/2 that looking at the coefficients in the balanced equation.
Then M H2SO4 = mols H2SO4/L H2SO4. You know mols and M, solve for L.