Asked by Momo
What volume of 18N H2SO4 is required to prepare 125 ml of 6.0 N H2SO4?
Answers
Answered by
DrBob222
mL1 x N1 = mL2 x N2
mL1 x 18 = 125 x 6.0
Solve for mL1.
mL1 x 18 = 125 x 6.0
Solve for mL1.
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