Asked by Cyn
Given the fuction y = log3(x+3)+2, calculate the zero of the function. GIve an exact answer.
Answers
Answered by
Reiny
So you want to set
log<sub>3</sub>(x+3) + 2 = 0
log<sub>3</sub>(x+3) = -2
by definition:
3^-2 = x+3
x = 1/9 - 3
x = -26/9
log<sub>3</sub>(x+3) + 2 = 0
log<sub>3</sub>(x+3) = -2
by definition:
3^-2 = x+3
x = 1/9 - 3
x = -26/9
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