Asked by Cyn

Given the fuction y = log3(x+3)+2, calculate the zero of the function. GIve an exact answer.
Answered by Reiny
So you want to set
log<sub>3</sub>(x+3) + 2 = 0
log<sub>3</sub>(x+3) = -2

by definition:
3^-2 = x+3
x = 1/9 - 3
x = -26/9