Asked by julie
Solve for x: log3(x^2-4)-log3(x+2)=2
Answers
Answered by
Reiny
log3(x^2-4)-log3(x+2)=2
log3 [(x^2-4)/x+2)] = 2
log3 [(x+2)(x-2)/(x+2)] = 2
log3 (x-2) = 2
x-2 = 3^2
x = 11
log3 [(x^2-4)/x+2)] = 2
log3 [(x+2)(x-2)/(x+2)] = 2
log3 (x-2) = 2
x-2 = 3^2
x = 11
Answered by
Adam
log3 (x^2-4) -log3 (x+2)=2
log3 [(x^2-4)/x+2)] = 2
log3 [(x+2)(x-2)/(x+2)] = 2
log3 (x-2) = 2
x-2 = 3^2
x = 11
log3 [(x^2-4)/x+2)] = 2
log3 [(x+2)(x-2)/(x+2)] = 2
log3 (x-2) = 2
x-2 = 3^2
x = 11
Answered by
Reiny
Adam, why would you just cut-and-paste my solution and claim it as yours ?
You didn't even bother to fix my error in the 2nd line, where I missed a bracket.
You didn't even bother to fix my error in the 2nd line, where I missed a bracket.
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